A NOTE ON CHARACTERIZATION OF NU (Dn)

A NOTE ON CHARACTERIZATION OF NU (Dn)

In this paper construction of normalizer of Dn in V (ZDn) is reduced to construction of integral group ring of its cyclic subgroup. In a better expression, we have shown that NU (Dn) = Dn × F, where F is a free abelian group with rank ρ = 1 2 ϕ(n) − 1.