Airat BİKCHENTAEV

The algebra of thin measurable operators is directly finite

The algebra of thin measurable operators is directly finite

Constructive Mathematical Analysis

2023-Cilt: 6 Sayı: 1

1-5

Hilbert space, von Neumann algebra, semifinite trace, $\tau$-measurable operator, $\tau$-compact operator, singular value function, idempotent

185 99